11 Aug
2009
11 Aug
'09
4:32 p.m.
- User logs in to imap from 192.168.0.1. What is foo's value?
protocol imap { remote_ip 192.168.0.0/16 { foo = foo } } remote_ip 192.168.0.0/24 { foo = bar }
This one is easy. It should be foo in any case :-)
Why? /24 is more specific than /16, but protocol imap is more specific than (implicit) protocol any. I assume this is why Timo included this example.
Gr.
Matthijs