26 Oct
2010
26 Oct
'10
5:03 p.m.
On Tue, 2010-10-26 at 16:00 +0200, Maciej Uhlig wrote:
I'd like to write post-login script using PHP. I noticed every shell post-login script ends with: exec "$@", which effectively executes dovecot's script-login.
$@ is all parameters.
However, while I try to do the same (?) in PHP: $prog = $argv[1]; exec ("$prog"); it doesn't work.
Here you're executing the program, but not giving it any parameters from $argv[2] etc. I don't know what is the correct way to do that in PHP.